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  1. Using the SCOTT schema, for each employee we want to know how many other people are in their department. -- Non-ANSI Syntax SELECT e.ename AS employee_name, dc.dept_count AS emp_dept_count FROM emp e, (SELECT deptno, COUNT(*) AS dept_count FROM emp GROUP BY deptno) dc WHERE e.deptno = dc.deptno; -- ANSI Syntax SELECT e.ename AS employee_name, dc.dept_count AS emp_dept_count FROM emp e JOIN (SELECT deptno, COUNT(*) AS dept_count FROM emp GROUP BY deptno) dc ON e.deptno = dc.deptno; -- Non-ANSI Syntax WITH dept_count AS ( SELECT deptno, COUNT(*) AS dept_count FROM emp GROUP BY deptno) SELECT e.ename AS employee_name, dc.dept_count AS emp_dept_count FROM emp e, dept_count dc WHERE e.deptno = dc.deptno; -- ANSI Syntax WITH dept_count AS ( SELECT deptno, COUNT(*) AS dept_count FROM emp GROUP BY deptno) SELECT e.ename AS employee_name, dc.dept_count AS emp_dept_count FROM emp e JOIN dept_count dc ON e.deptno = dc.deptno; The difference seems rather insignificant here.